"?nter a triangle and calculate the sine of its maximal angle. The triangle is defined by the coordinates of its vertices. The coordinates are floating-point numbers." The truth is that I am falling behind class and I can't type the code... trying to get back on track, but I don't have enough time to solve this issue by myself.
We won't do your homework for you. Though think back to trig. sin(θ) = opposite / hypotenuse So you coordinates are floating point numbers. That all well and good. You need to define your three sides. Coordinate1 = A Coordinate2 = B Coordinate3 = C The distance between these points will be the length of that side. Remember your distance formula is sqrt((x_2-x_1)^2+(y_2-y_1)^2) Once you define you sides, you can find the angle by taking the inverse sin. So θ = sin^-1(o/h)
Go for it. There is probably an easier way to do it via loops, but here is a starter. Ex. float pointAx = 2.6542 float pointAy = 1.9542 float pointBx = 1.2458 float pointBy = 2.6542 float pointCx = 4.2698 float pointCy = 1.2378 float sideAB = 0.0; float sideAC = 0.0; float sideBC = 0.0; sideAB = sqrt((pointBx)^2-(pointAx)^2)+((pointBy)^2-(pointAy)^2))
