hello there, im just wondering if i bot only pvp is there a less chance to get ban or even with 1 min u can get ban? i used before honobuddy for about 3 moonth and got banned for boting but i boted everything posible grinding/questing/farming nodes etc etc...now im litl bit affraid cuz maybe they track me or something cuz im having every 3-4 hrs a disconect dont know why now i just wanna do pvp bot for about 3-4 hrs per day. if this is wrong section or question pls forgive me im just curious ty al 4 answers
When I bot I tried to avoid players, PvP botting is the opposite of that. People aren't stupid and can spot a bot instantly, you'll just get reported and probably banned.
Bots aren't the most hated thing in a rbg. I personally think afk'ers are worse. But if the bot gets stuck or paused in any way, boom you're 'afk' and that's doubly bad. In battle for gilneas battleground, one of the spirit ressers glitched and despawned. Everyone had to run to the original spawn point and res there. Well sure enough, all the bots got stuck there, just sitting for the rest of the BG. I was there to get it back on track, but it was so obvious who the botters were when a bug trips them all up. Also, I don't think you can make a custom profile for the BG's, they all run on the same default. Eventually, the bots sort of accumulate after a fight and all mount/follow each other around on the same track. Sure, people just blindly follow each other in rbg's anyway, but it looks very sketchy. When honorbuddy first came out, could grind honor pretty much 24/7 and no one was the wiser. But seriously, 1/3 of the bg is bots now and I think even doing it for an hour is a huge risk.
Let me calculate the odds for you rq. First we find ∫[-∞..∞] e^(-x²) dx Now since e^(-x²) is an even function, then: I = ∫[-∞..∞] e^(-x²) dx I = 2 ∫[0..∞] e^(-x²) dx I² = 4 ∫[0..∞] e^(-x²) dx ∫[0..∞] e^(-x²) dx I² = 4 ∫[0..∞] e^(-x²) dx ∫[0..∞] e^(-y²) dy (Note: changing variable in integral will not change value of definite integral) I² = 4 ∫[0..∞] ∫[0..∞] e^(-(x²+y²)) dy dx I²/4 = ∫[0..∞] (∫[0..∞] e^(-(x²+y²)) dy) dx Let y = xs . . . . . . . . . . when y = 0, s = 0 then dy = x ds . . . . . . . as y → ∞, s → ∞ (since x > 0) I²/4 = ∫[0..∞] (∫[0..∞] e^(-(x²+x²s²)) x ds) dx I²/4 = ∫[0..∞] (∫[0..∞] x e^(-x²(1+s²)) dx) ds I²/4 = ∫[0..∞] (1/(-2(1+s²)) e^(-x²(1+s²))) |[0..∞] ds I²/4 = ∫[0..∞] (0 - 1/(-2(1+s²))) ds I²/4 = 1/2 ∫[0..∞] 1/(1+s²) ds I²/4 = 1/2 arctan(s) |[0..∞] ds I²/4 = 1/2 (arctan(∞) - arctan(0)) = 1/2 (π/2 - 0) I²/4 = π/4 I² = π I = √π ∫[-∞..∞] e^(-x²) dx = √π Now we find ∫[-∞..∞] 1/√(2π) e^(-½x²) dx Let u² = ½x² u = x/√2 du = 1/√2 dx As x → ±∞ then u → ±∞, so limits of integration do not change ∫[-∞..∞] 1/√(2π) e^(-½x²) dx = 1/√π ∫[-∞..∞] 1/√2 e^(-½x²) dx = 1/√π ∫[-∞..∞] e^(-u²) du = 1/√π ∫√π = √π/√π = 1 1= 100%, you have 100% chance of getting banned if you bot 3-4 hours a day.
Since bots, at least bgfarmer, play better/smarter than most of those scrubs in bgs, chances to get reported and banned are quite low. If u have balls you bot 100 % afk, if you dont have balls you supervise ur bot and you will be fine.
Botted 3-4 hours a day up to 2200 in rbg's. Supervise it, let it do the combat while you do the cc and movemnt, and you should be fine.
